Identifying and Correcting Errors Practice

alphabet = "abcdefghijklmnopqrstuvwxyz"

alphabetList = []

for i in alphabet:
    alphabetList.append(i)

print(alphabetList)

# case 1: using while loop
letter = input("What letter would you like to check?")

i = 0
pos = -1
while i < 26:
    if alphabetList[i] == letter:
        print("The letter " + letter + " is the " + str(i) + " letter in the alphabet")
        pos = i
        break
    i += 1
    
# test case
if pos == -1:
    print("The letter " + letter + " is not in the alphabet")
elif alphabetList[pos] != letter:
    print("The letter " + letter + " is not the " + str(pos) + " letter in the alphabet")

['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
The letter 8 is not in the alphabet

alphabet = "abcdefghijklmnopqrstuvwxyz"

alphabetList = []

for i in alphabet:
    alphabetList.append(i)

print(alphabetList)


# case 1: using for loop
# move the count = 0 outside of the for loop
letter = input("What letter would you like to check?")
count = 0
pos = -1
for i in alphabetList:
    if i == letter:
        print("The letter " + letter + " is the " + str(count) + " letter in the alphabet")
        pos = count
        break
    count += 1

# test case
if pos == -1:
    print("The letter " + letter + " is not in the alphabet")
elif alphabetList[pos] != letter:
    print("The letter " + letter + " is not the " + str(pos) + " letter in the alphabet")

['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
The letter a is the 0 letter in the alphabet

odds = []
i = 1


while i <= 10:
    odds.append(i)
    i += 2

print(odds)

[1, 3, 5, 7, 9]

numbers = [0,1,2,3,4,5,6,7,8,9,10]
odds = []

for i in numbers:
    if (numbers[i] % 2 != 0):
        odds.append(numbers[i])

print(odds)

[1, 3, 5, 7, 9]

numbers = []
newNumbers = []
i = 0

while i < 100:
    numbers.append(i)
    i += 1

for i in numbers:
    if numbers[i] % 5 == 0:
        newNumbers.append(numbers[i])
    elif numbers[i] % 2 == 0:
        newNumbers.append(numbers[i])

print(newNumbers)

[0, 2, 4, 5, 6, 8, 10, 12, 14, 15, 16, 18, 20, 22, 24, 25, 26, 28, 30, 32, 34, 35, 36, 38, 40, 42, 44, 45, 46, 48, 50, 52, 54, 55, 56, 58, 60, 62, 64, 65, 66, 68, 70, 72, 74, 75, 76, 78, 80, 82, 84, 85, 86, 88, 90, 92, 94, 95, 96, 98]

Challenge

# Also test if user input is on the menu, e.g. if inputted 'pizza' it will output that it is not on the menu
menu =  {"burger": 3.99,
         "fries": 1.99,
         "drink": 0.99}
total = 0

#shows the user the menu and prompts them to select an item
print("Menu")
for k,v in menu.items():
    print(k + "  $" + str(v)) #why does v have "str" in front of it?

#ideally the code should prompt the user multiple times
while True:
    item = input("Please select an item from the menu. Type q if done\n")
    if item == 'q':
       print("Thanks for your selection\n")
       break
    elif item not in menu.keys():
       print(item + " is not in menu, please reselect\n")
    else:
       print("you have selected "+item+", price is "+str(menu[item])+"\n")
       total += menu[item]

#code should add the price of the menu items selected by the user 
print("Your total is "+str(total))

Menu
burger  $3.99
fries  $1.99
drink  $0.99
you have selected burger, price is 3.99

milkshake is not in menu, please reselect

you have selected fries, price is 1.99

Thanks for your selection

Your total is 5.98